Comments (4)

1. I’ve read a few of Feynman’s books / books about Feynman. The math and science are usually way over my head, except when they give examples of his ability to break things down into wonderfully concise, yet not condescending, explanations. I think he must have been a real pain in the a$$ at times, and I think I would have absolutely loved the guy.

   posted by caitlen315 on 6-5-2008 at 10:18 am

2. The article mentions Feynman’s setting up some of the first “plug-programmable tabulating machines”. His work was likely influence by Wallace Eckert at Columbia. Wallace was an astronomer responsible for creating tables of the movement of heavenly bodies. He initially used young women with adding machines. He kept pushing the envelope, using punch cards and beyond. You can click on the link from my name to read an article on Eckert and computing.

   posted by Stew on 6-5-2008 at 12:41 pm

3. They had a Connection Machine at FSU when I was there during high school. I asked the grad student showing us around if the blinking lights indicated anything about processor activity. He said you could program them to, but mostly they were there “just to impress the generals.”

   posted by Michael Higgins on 6-8-2008 at 9:50 am

4. Einstein’s Nemesis: DI Her Eclipsing Binary Stars Solution
   The problem that the 100,000 PHD Physicists could not solve

   This is the solution to the “Quarter of a century” Smithsonian-NASA Posted motion puzzle that Einstein and the 100,000 space-time physicists including 109 years of Nobel prize winner physics and physicists and 400 years of astronomy and Astrophysicists could not solve and solved here and dedicated to Drs Edward Guinan and Frank Maloney
   Of Villanova University Pennsylvania who posted this motion puzzle and started the search collections of stars with motion that can not be explained by any published physics
   For 350 years Physicists Astrophysicists and Mathematicians and all others including Newton and Kepler themselves missed the time-dependent Newton’s equation and time dependent Kepler’s equation that accounts for Quantum – relativistic effects and it explains these effects as visual effects. Here it is

   Universal- Mechanics

   All there is in the Universe is objects of mass m moving in space (x, y, z) at a location
   r = r (x, y, z). The state of any object in the Universe can be expressed as the product

   S = m r; State = mass x location

   P = d S/d t = m (d r/dt) + (dm/dt) r = Total moment

   = change of location + change of mass

   = m v + m’ r; v = velocity = d r/d t; m’ = mass change rate

   F = d P/d t = d²S/dt² = Force = m (d²r/dt²) +2(dm/d t) (d r/d t) + (d²m/dt²) r

   = m γ + 2m’v +m”r; γ = acceleration; m” = mass acceleration rate

   In polar coordinates system

   r = r r(1) ;v = r’ r(1) + r θ’ θ(1) ; γ = (r” – rθ’²)r(1) + (2r’θ’ + rθ”)θ(1)

   F = m[(r"-rθ'²)r(1) + (2r'θ' + rθ")θ(1)] + 2m’[r'r(1) + rθ'θ(1)] + (m”r) r(1)

   F = [d²(m r)/dt² - (m r)θ'²]r(1) + (1/mr)[d(m²r²θ')/d t]θ(1) = [-GmM/r²]r(1)

   d² (m r)/dt² – (m r) θ’² = -GmM/r²; d (m²r²θ’)/d t = 0

   Let m =constant: M=constant

   d²r/dt² – r θ’²=-GM/r² —— I

   d(r²θ’)/d t = 0 —————–II
   r²θ’=h = constant ————– II
   r = 1/u; r’ = -u’/u² = – r²u’ = – r²θ’(d u/d θ) = -h (d u/d θ)
   d (r²θ’)/d t = 2rr’θ’ + r²θ” = 0 r” = – h d/d t (du/d θ) = – h θ’(d²u/d θ²) = – (h²/r²)(d²u/dθ²)
   [- (h²/r²) (d²u/dθ²)] – r [(h/r²)²] = -GM/r²
   2(r’/r) = – (θ”/θ’) = 2[λ + ỉ ω (t)] – h²u² (d²u/dθ²) – h²u³ = -GMu²
   d²u/dθ² + u = GM/h²
   r(θ, t) = r (θ, 0) Exp [λ + ỉ ω (t)] u(θ,0) = GM/h² + Acosθ; r (θ, 0) = 1/(GM/h² + Acosθ)
   r ( θ, 0) = h²/GM/[1 + (Ah²/Gm)cosθ]
   r(θ,0) = a(1-ε²)/(1+εcosθ) ; h²/GM = a(1-ε²); ε = Ah²/GM

   r(0,t)= Exp[λ(r) + ỉ ω (r)]t; Exp = Exponential

   r = r(θ , t)=r(θ,0)r(0,t)=[a(1-ε²)/(1+εcosθ)]{Exp[λ(r) + ì ω(r)]t} Nahhas’ Solution

   If λ(r) ≈ 0; then:

   r (θ, t) = [(1-ε²)/(1+εcosθ)]{Exp[ỉ ω(r)t]

   θ’(r, t) = θ’[r(θ,0), 0] Exp{-2ỉ[ω(r)t]}

   h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity
   h = 2πa²√ (1-ε²); r (0, 0) = a (1-ε)

   θ’ (0,0) = h/r²(0,0) = 2Ï€[√(1-ε²)]/T(1-ε)²
   θ’ (0,t) = θ’(0,0)Exp(-2ỉwt)={2Ï€[√(1-ε²)]/T(1-ε)²} Exp (-2iwt)

   θ’(0,t) = θ’(0,0) [cosine 2(wt) - ỉ sine 2(wt)] = θ’(0,0) [1- 2sine² (wt) - ỉ sin 2(wt)]
   θ’(0,t) = θ’(0,t)(x) + θ’(0,t)(y); θ’(0,t)(x) = θ’(0,0)[ 1- 2sine² (wt)]
   θ’(0,t)(x) – θ’(0,0) = – 2θ’(0,0)sine²(wt) = – 2θ’(0,0)(v/c)² v/c=sine wt; c=light speed

   Δ θ’ = [θ'(0, t) - θ'(0, 0)] = -4Ï€ {[√ (1-ε) ²]/T (1-ε) ²} (v/c) ²} radians/second
   {(180/Ï€=degrees) x (36526=century)

   Δ θ’ = [-720x36526/ T (days)] {[√ (1-ε) ²]/ (1-ε) ²}(v/c) = 1.04°/century

   This is the T-Rex equation that is going to demolished Einstein’s space-jail of time

   The circumference of an ellipse: 2Ï€a (1 – ε²/4 + 3/16(ε²)²—) ≈ 2Ï€a (1-ε²/4); R =a (1-ε²/4)
   v (m) = √ [GM²/ (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m

   posted by joe nahhas on 1-29-2009 at 2:48 am

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