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	<title>Comments on: Brain Game: Mrs. Sasse&#8217;s Class</title>
	<atom:link href="http://www.mentalfloss.com/blogs/archives/39457/feed" rel="self" type="application/rss+xml" />
	<link>http://www.mentalfloss.com/blogs/archives/39457</link>
	<description>Feel Smart Again</description>
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		<title>By: Sandy Wood</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-229360</link>
		<dc:creator>Sandy Wood</dc:creator>
		<pubDate>Wed, 04 Nov 2009 02:27:09 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-229360</guid>
		<description>Andrew, nice call on the variables - I did the same exact thing when devising the puzzle.</description>
		<content:encoded><![CDATA[<p>Andrew, nice call on the variables &#8211; I did the same exact thing when devising the puzzle.</p>
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		<title>By: Andrew</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-229110</link>
		<dc:creator>Andrew</dc:creator>
		<pubDate>Tue, 03 Nov 2009 20:09:45 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-229110</guid>
		<description>To keep the variables straight I used the second letter of their names.  Wyatt = Y, Wendy = E.... on to A, O, and I.

It was pretty easy; once I saw that Y = 6*O my &quot;order of magnitude&quot; sense told me that O was going to be either 1 or 2.</description>
		<content:encoded><![CDATA[<p>To keep the variables straight I used the second letter of their names.  Wyatt = Y, Wendy = E&#8230;. on to A, O, and I.</p>
<p>It was pretty easy; once I saw that Y = 6*O my &#8220;order of magnitude&#8221; sense told me that O was going to be either 1 or 2.</p>
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	<item>
		<title>By: Larchie</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-229075</link>
		<dc:creator>Larchie</dc:creator>
		<pubDate>Tue, 03 Nov 2009 18:50:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-229075</guid>
		<description>I don&#039;t like trial and error with all the arithmetic, so my key was to recognize that Willy must be the odd vote total because:

Given: Wyatt=x, Willy=y

x + (3/6)x + (2/6)x + (1/6)x + y = 31

reduces to:

2x + y = 31

2 times any number is even, so Willy (y) must be odd to get an odd sum (31).

And Wyatt (x) and must be a multiple of 6, and must be less than 15.

So Wyatt must be 12.</description>
		<content:encoded><![CDATA[<p>I don&#8217;t like trial and error with all the arithmetic, so my key was to recognize that Willy must be the odd vote total because:</p>
<p>Given: Wyatt=x, Willy=y</p>
<p>x + (3/6)x + (2/6)x + (1/6)x + y = 31</p>
<p>reduces to:</p>
<p>2x + y = 31</p>
<p>2 times any number is even, so Willy (y) must be odd to get an odd sum (31).</p>
<p>And Wyatt (x) and must be a multiple of 6, and must be less than 15.</p>
<p>So Wyatt must be 12.</p>
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	<item>
		<title>By: HeyBeckyJ</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-229046</link>
		<dc:creator>HeyBeckyJ</dc:creator>
		<pubDate>Tue, 03 Nov 2009 17:56:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-229046</guid>
		<description>Great puzzle!  Keeping the names/variables straight was almost more challenging than answering the question.  :)</description>
		<content:encoded><![CDATA[<p>Great puzzle!  Keeping the names/variables straight was almost more challenging than answering the question.  :)</p>
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	</item>
	<item>
		<title>By: sam</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-229012</link>
		<dc:creator>sam</dc:creator>
		<pubDate>Tue, 03 Nov 2009 16:53:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-229012</guid>
		<description>willy:7
wyatt:12
wendy:6
wally:4
woody:2</description>
		<content:encoded><![CDATA[<p>willy:7<br />
wyatt:12<br />
wendy:6<br />
wally:4<br />
woody:2</p>
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		<title>By: Sandy Wood</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-228996</link>
		<dc:creator>Sandy Wood</dc:creator>
		<pubDate>Tue, 03 Nov 2009 16:16:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-228996</guid>
		<description>Christine, I&#039;m afraid that answer doesn&#039;t quite work.

Remember in the clues that Wyatt earned twice as many votes as Wendy.

Your solution has Wyatt with 20 and Wendy with 4, which would be five times as many.</description>
		<content:encoded><![CDATA[<p>Christine, I&#8217;m afraid that answer doesn&#8217;t quite work.</p>
<p>Remember in the clues that Wyatt earned twice as many votes as Wendy.</p>
<p>Your solution has Wyatt with 20 and Wendy with 4, which would be five times as many.</p>
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	<item>
		<title>By: Ryan Smith</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-228989</link>
		<dc:creator>Ryan Smith</dc:creator>
		<pubDate>Tue, 03 Nov 2009 16:08:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-228989</guid>
		<description>Silly me, I misread others&#039; solutions, previous comment withdrawn :-)</description>
		<content:encoded><![CDATA[<p>Silly me, I misread others&#8217; solutions, previous comment withdrawn :-)</p>
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	<item>
		<title>By: Ryan Smith</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-228986</link>
		<dc:creator>Ryan Smith</dc:creator>
		<pubDate>Tue, 03 Nov 2009 16:05:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-228986</guid>
		<description>I&#039;m not sure where others are getting it, but the solution 31 votes for Wyatt and 0 votes for all other candidates is not possible.  The description states that Wyatt&#039;s vote count is equal to 2 times, 3 times, and 6 times the votes of Wendy, Wally, and Woody respectively.  As 0 times any number is still 0, the 31-0-0-0-0 solution is not correct.</description>
		<content:encoded><![CDATA[<p>I&#8217;m not sure where others are getting it, but the solution 31 votes for Wyatt and 0 votes for all other candidates is not possible.  The description states that Wyatt&#8217;s vote count is equal to 2 times, 3 times, and 6 times the votes of Wendy, Wally, and Woody respectively.  As 0 times any number is still 0, the 31-0-0-0-0 solution is not correct.</p>
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	<item>
		<title>By: Rod</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-228980</link>
		<dc:creator>Rod</dc:creator>
		<pubDate>Tue, 03 Nov 2009 15:53:38 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-228980</guid>
		<description>I started with algebra, but once it dawned on me that you cant have partial vote, gridding it was way easier</description>
		<content:encoded><![CDATA[<p>I started with algebra, but once it dawned on me that you cant have partial vote, gridding it was way easier</p>
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	<item>
		<title>By: SP</title>
		<link>http://www.mentalfloss.com/blogs/archives/39457/comment-page-1#comment-228960</link>
		<dc:creator>SP</dc:creator>
		<pubDate>Tue, 03 Nov 2009 15:10:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.mentalfloss.com/blogs/?p=39457#comment-228960</guid>
		<description>I got the above solution, but there&#039;s an alternate:

Wally: 0
Wendy: 0
Willy: 31
Woody: 0
Wyatt: 0</description>
		<content:encoded><![CDATA[<p>I got the above solution, but there&#8217;s an alternate:</p>
<p>Wally: 0<br />
Wendy: 0<br />
Willy: 31<br />
Woody: 0<br />
Wyatt: 0</p>
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